About the Mean Value Theorem.




Dr. Wei-Chi Yang

Radford University

Radford, VA 24142

www.radford.edu/~wyang

The Cauchy Mean Value Theorem.

Suppose the function MATH and MATH are continuous and that their restrictions to $(a,b)$ are differentiable. Moreover, assume that MATH for all $x$ in $(a,b).$ Then there is a point $x_{0}$ in $(a,b)$ at whichMATH

$\QTR{bf}{Remark:}$ This is not intuitive at all, we should see how this can be made eaiser to understand from geometric point of view.

  1. Cauchy Mean Value Theorem, Inequality Version. If functions $f$ and $g$ are continuous on $[a,b]$ and differentiable on $(a,b),$ and if $g$ is strictly monotone, then MATHimpliesMATH

  2. Mean Value Theorem, Inequality Version.MATHimpliesMATH

  3. A Physical Application: If car $A$ is going at a speed which is between $2$ and $3$ times the speed of car $B,$then car $A$ will have traveled between $2$ and $3$ times of the distance of car $B.$[R. Vencil Skarda of Brigham Young University]

Example.

Let MATHand we may pick $g(x)$ to be any function that satisfies the conditions of the theorem. Note that one easy way to find $g$ is to graph its derivative so $y=g\prime (x)$ does not touch $x$-axis. Say, MATH, then $g(x)=-\cos (x)+2x$.

We first sketch the graphs of $f(x)$ and $g(x)$ in $[-5,5]$ as follows: $f$
graphics/CauchyMeanValueweb__47.png

If $f$ and $g$ satisfy the conditions of Cauchy Mean Value, can we find $F$ so that $F$ satisies the Rolle's Theorem

  1. One way to interpret the Cauchy Mean Value Theorm is that if we are given a strictly monotone function $g$ on $(a,b)$ (since MATH on $(a,b)),$ and if $f$ is arbitrary differentiable function on $(a,b),$ we can find a function $F$ such that $F$ satisfies the Rolle's Theorem. [We may define MATH]

  2. Another way to interpret the Cauchy Mean Value Theorem is that if the function $F$ is defined to be $f(x)+m\ast g(x),$where $f$ and $g$ are continuous on $[a,b]$ and differentiable in $(a,b),$ and $g$ is strictly monotone. Then by compressing or stretching $g(x)$ and adds it to $f,$ we can find a number $m$ (which can be MATH ) and $x_{0}$ in $(a,b)$ so that MATH

One question here: Is the number $m$ is unique for MATH

  1. Note that if MATHthen MATH implies that MATH for some $x_{0}$ in $(a,b).$If we use the Example 2 above, we see MATH and MATH and assume $[a,b]=[-2,1].$We have MATH and MATH

  2. We link to Maple. Note that if we follow the curve where $z=F(x,y)$ and MATH intersect, then we will get $F^{\prime }(x)=0.$[Or precisely, MATH] Note that if we follow the curve MATH the changes of $F$ with respect to $x$ direction is $0.$ ]

Express $F$ as a composite of $f$ and $g^{-1}.$

  1. Another way to interpret Cauchy Mean Value Theorem: Let $f$: $X\rightarrow Y$ and $g:X\rightarrow Y$. The functions $f$ and $g$ are continuous on $X$, and $f$ and $g$ are differentiable on the interiors of $X$. If the function $g$ is strictly monotone (WLOG, we assume $g$ is strictly increasing here), then we define MATHMATHwhere $x=g^{-1}(y).$Therefore, we apply the regular Mean Value Theorem on $F=f\circ g^{-1},$ which says that there is a $g(c)$ between $(g(a),g(b))$ such that MATH

Remark: One draw back of writing $F$ as $f\circ g^{-1}$ can be shown as follows: Note that if we take the same $f,$ and replace $g(x)$ by $-\cos x+2x,$ then $g$ is strictly increasing, but we may not be able to find a formula for $g^{-1}$so we can not define $F$ this way.

Parametric Form

Consider a curve of the form $r=f(\theta ).$If the curve is a smooth curve in the interval $[a,b]$, it follows from MVT that we can find $\theta \in (a,b)$ so that

MATH




This implies that MATHintegrating over $\theta $ on both sides, we getMATH




If we define MATH we will see $F(a)=F(b),$ and we may apply the Rolle's theorem on $F$. This gives us a glimpse how we prove the Cauchy Mean Value Theorem.

Example

We consider $r=\theta ,$and we write

MATHWe haveMATHSince the curve $r=\theta $ is a smooth curve, it follows from the Mean Value Theorem that there exists a $\theta $ such that MATHIf we pick MATHwe can solve MATHSolution is$\allowbreak $ MATH from ClassPad.