> 796 pbjbj <#`IIIII]]]8]"8c"e"e"e"e"e"e"#&|e"Ie"IIz"dIIc"c"V_!@#"#]!O""0"!x'4'#"'I#",e"e""' : Standard Scores, Percentiles, and the Normal Curve
Please show all of your work for each of the following problems.
For the following sample of scores, please
a). calculate the standard deviation
b). convert each raw score to a standard score
c). convert each raw score to a percentile score
X
--
8
9
12
15
16
---
Draw the normal curve and, on the x-axis, label the standard scores ranging from -3 to +3 (you only need to use whole numbers).
Find the percentile scores and T-Scores that correspond to each of the following standard scores: +1.6, -1.6, 0.0, +2.9, -.53
Going back to the graph of the normal curve you drew in question 2, please write in the percentile score for each standard score (i.e., -3, -2) just below that standard score.
An employee has a rating of 5.7 on a measure of job performance. The mean for employees at that company is 5.5 and the standard deviation is .4. What is that employees percentile score for job performance? What is their T-Score?
When answering the questions below, it will be helpful to start by drawing a graph of the normal curve.
For a normally distributed set of raw scores, what percentage of scores fall between a z-score of -1.62 and +2.30?
For a normally distributed set of raw scores, what percentage of raw scores fall between a z-score of +0.83 and a z-score of +2.15?
For a normally distributed set of raw scores, what percentage of raw scores fall between a z-score of -.65 and a z-score of -.87?
A psychologist is using a questionnaire measure of depression to help in diagnosing clients with depression. The manual for the questionnaire indicates that clients who score in the top 5% on the questionnaire fall in the "clinically depressed" range. The mean of all of scores on the questionnaire is 22 and the standard deviation of scores on the questionnaire is 5. What is the highest raw score that a client could get on the questionnaire and still not be considered to be clinically depressed?
An employer who runs a customer service-oriented business wants to gives a bonus to the 20% of employees who had the fewest number of customer complaints per week of work. The mean number of complaints per week of work is .6 and the standard deviation for this measure is .1. What is the highest number of complaints per week that an employee could have and still get the bonus?
A company develops a measure of leadership effectiveness in order to identify entry-level employees for management trainee positions. The mean score for 500 employees taking the test is 55 and the standard deviation is 8. The company decides to invite employees scoring in the top 9% on the test to enroll in the management trainee program. What is the lowest score that someone could get on the test and still qualify for the program?
The mean of a set of scores is 35 and the standard deviation is 7. What percentage of scores fall between the raw scores of 37 and 41? What are the percentile scores that correspond to the raw scores of 26, 35, and 43? What percentage of scores fall between the raw scores of 31 and 44?
In order to eliminate potential outliers from her data set an investigator decides to remove the 1% of scores that she was least likely to get just by chance (the 1% of scores that are furthest away from the mean). The mean of the scores is 363 and the standard deviation is 41. What is the lowest raw score she is willing to retain in her data set. What is the highest score she is willing to keep?
A psychologist develops a test for sustained attention in which the mean raw scores for this test is 77 and the standard deviation is 12. The researcher would like to report each childs score as a T-score. Two children have raw scores of 65 and 93. What are the T-scores for these two children?
A company has developed a new achievement test for sustained attention. The mean raw score for a validation sample of 500 fourth grade children is 347 and the standard deviation is 56. The company wants to report scores is SAT/GRE units (mean of 500 and a standard deviation of 100). Two children have scores of 325 and 422. What should the company report as their transformed scores?
The mean of a set of scores is 45 and the standard deviation of this set of scores is 12. What two raw scores define the lower and upper limits of the 95% confidence interval around this mean?
3
"
`acdfghiklopº´´´
h
j^Jjh
jUh
jjh
jU^JhyY@OJQJ^J"h|J56@OJQJ\]^Jh|J@OJQJ^J
h|JCJ 34uvw- . 2 7 ; ? M [ i x y y
z
*+
hd*$^h
&Fd*$d*$$a$}~v
w
uv-.PQ^
hd*$^h
&Fd*$d*$^_`bcefghjkmnopdd*$:....()()))()()00P8$BP/ =!"#$%Dp^!666666666vvvvvvvvv66666686666666666666666666666666666666666666666666666666hH6666666666666666666666666666666666666666666666666666666666666666662 0@P`p2( 0@P`p 0@P`p 0@P`p 0@P`p 0@P`p 0@P`p8XV~_HmH nH sH tH X`XNormal1$7$8$H$$CJOJQJ^J_HaJmH sH tH Z@Z Heading 1$$d*$@&a$6@OJQJ]^JDA DDefault Paragraph FontViV
0Table Normal :V44
la(k (
0No List8+8Endnote Text^J>*>Endnote ReferenceH*::
Footnote Text^J@&!@Footnote ReferenceH*TT
TOC 1/
$
0d*$]^`0PP
TOC 2+
$
0d*$]^`0PP
TOC 3+
$
p0d*$]^p`0PP
TOC 4+
$
@0d*$]^@`0PP
TOC 5+
$
0d*$]^`0HH
TOC 6#
$0d*$^`0@@
TOC 70d*$^`0HH
TOC 8#
$0d*$^`0HH
TOC 9#
$
0d*$^`0T
T
Index 1+
$
`d*$]^``TT
Index 2+
$
0d*$]^`0D.DTOA Heading
$d*$.".Caption^J:/:_Equation CaptionPK![Content_Types].xmlj0Eжr(Iw},-j4 wP-t#bΙ{UTU^hd}㨫)*1P' ^W0)T9<l#$yi};~@(Hu*Dנz/0ǰ$X3aZ,D0j~3߶b~i>3\`?/[G\!-Rk.sԻ..a濭?PK!֧6_rels/.relsj0}Q%v/C/}(h"O
= C?hv=Ʌ%[xp{۵_Pѣ<1H0ORBdJE4b$q_6LR7`0̞O,En7Lib/SeеPK!kytheme/theme/themeManager.xmlM
@}w7c(EbˮCAǠҟ7՛K
Y,
e.|,H,lxɴIsQ}#Ր ֵ+!,^$j=GW)E+&
8PK!Ptheme/theme/theme1.xmlYOo6w toc'vuر-MniP@I}úama[إ4:lЯGRX^6؊>$!)O^rC$y@/yH*)UDb`}"qۋJחX^)I`nEp)liV[]1M<OP6r=zgbIguSebORD۫qu gZo~ٺlAplxpT0+[}`jzAV2Fi@qv֬5\|ʜ̭NleXdsjcs7f
W+Ն7`gȘJj|h(KD-
dXiJ؇(x$(:;˹!I_TS1?E??ZBΪmU/?~xY'y5g&/ɋ>GMGeD3Vq%'#q$8K)fw9:ĵ
x}rxwr:\TZaG*y8IjbRc|XŻǿI
u3KGnD1NIBs
RuK>V.EL+M2#'fi~Vvl{u8zH
*:(W☕
~JTe\O*tHGHY}KNP*ݾ˦TѼ9/#A7qZ$*c?qUnwN%Oi4=3ڗP
1Pm\\9Mؓ2aD];Yt\[x]}Wr|]g-
eW
)6-rCSj
id DЇAΜIqbJ#x꺃6k#ASh&ʌt(Q%p%m&]caSl=X\P1Mh9MVdDAaVB[݈fJíP|8քAV^f
Hn-"d>znǊ ة>b&2vKyϼD:,AGm\nziÙ.uχYC6OMf3or$5NHT[XF64T,ќM0E)`#5XY`פ;%1U٥m;R>QDDcpU'&LE/pm%]8firS4d7y\`JnίIR3U~7+#mqBiDi*L69mY&iHE=(K&N!V.KeLDĕ{D vEꦚdeNƟe(MN9ߜR6&3(a/DUz<{ˊYȳV)9Z[4^n5!J?Q3eBoCMm<.vpIYfZY_p[=al-Y}Nc͙ŋ4vfavl'SA8|*u{-ߟ0%M07%<ҍPK!
ѐ'theme/theme/_rels/themeManager.xml.relsM
0wooӺ&݈Э5
6?$Q
,.aic21h:qm@RN;d`o7gK(M&$R(.1r'JЊT8V"AȻHu}|$b{P8g/]QAsم(#L[PK-![Content_Types].xmlPK-!֧6+_rels/.relsPK-!kytheme/theme/themeManager.xmlPK-!Ptheme/theme/theme1.xmlPK-!
ѐ' theme/theme/_rels/themeManager.xml.relsPK]
p"p
^p8@0(
B
S ?_``bbccefghjkmnq%Bw*
``bbccefghjkmnq3333333" _q-86|#W$(ebr|SԜ!^`o(.^`.pLp^p`L.@@^@`.^`.L^`L.^`.^`.PLP^P`L.^`o(.^`.pLp^p`L.@@^@`.^`.L^`L.^`.^`.PLP^P`L.^`o(.^`.pLp^p`L.@@^@`.^`.L^`L.^`.^`.PLP^P`L.-8#Wbr|S H qgKyY|J
j~`b@p`@UnknownG* Times New Roman5Symbol3.* Arial?= * Courier NewA BCambria Math")FFF!)PxxdXX2Q)PHX $PyY2!xx
PSYC 201 - Dr
Tom PierceRadford UniversityOh+'0 ,
LXd
p|PSYC 201 - DrTom PierceNormal.dotmRadford University2Microsoft Office Word@@Ɩ@pV@pV՜.+,0hp
Radford UniversityXPSYC 201 - DrTitle
!"#$%'()*+,-/0123458Root Entry F#:1Table.'WordDocument<#SummaryInformation(&DocumentSummaryInformation8.CompObjy
F'Microsoft Office Word 97-2003 Document
MSWordDocWord.Document.89q