{VERSION 5 0 "IBM INTEL NT" "5.0" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 1 }{CSTYLE "" -1 256 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 } {CSTYLE "" -1 257 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 258 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 259 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 }{PSTYLE "Normal" -1 0 1 {CSTYLE "" -1 -1 "Tim es" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }1 1 0 0 0 0 1 0 1 0 2 2 0 1 } {PSTYLE "Title" -1 18 1 {CSTYLE "" -1 -1 "Times" 1 18 0 0 0 1 2 1 1 2 2 2 1 1 1 1 }3 1 0 0 12 12 1 0 1 0 2 2 19 1 }{PSTYLE "Normal" -1 256 1 {CSTYLE "" -1 -1 "Times" 1 14 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }1 1 0 0 0 0 1 0 1 0 2 2 0 1 }} {SECT 0 {EXCHG {PARA 18 "" 0 "" {TEXT -1 36 "Parametric Equations and \+ Arc Lengths" }}{PARA 0 "" 0 "" {TEXT -1 42 "Exercises: page 471, #5,7, 9,11,13, 17, 19." }}{PARA 0 "" 0 "" {TEXT -1 10 "Example 1." }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 21 "x:=ln(t); y:=exp(-t);" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 19 "plot([x,y,t=1..2]);" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 14 "d1:=diff(x,t);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 14 "d2:=diff(y,t);" }}}{EXCHG {PARA 0 " > " 0 "" {MPLTEXT 1 0 28 "h:=t->((d1)^2+(d2)^2)^(1/2);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 5 "h(t);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 40 "L:=Int(((d1)^2+(d2)^2)^(1/2),t=0..2*Pi);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 9 "evalf(%);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 14 "with(student):" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 33 "evalf(simpson(h(t), t=1..2, 10));" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 9 "?simpson;" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 33 "evalf(middlesum(h(t),t=1..2,10));" }}{PARA 0 "> " 0 " " {MPLTEXT 1 0 33 "evalf(trapezoid(h(t),t=1..2,10));" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 21 "x:=cos(t); y:=sin(t);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 22 "plot([x,y,t=0..2*Pi]);" }}}{EXCHG {PARA 0 " " 0 "" {TEXT -1 73 "The following command is to find the arc length of a parametric equation:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 52 " L:=Int((diff(x,t)^2+(diff(y,t)^2))^(1/2),t=0..2*Pi);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 9 "evalf(%);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 42 "plot([x,y,t=0..2*Pi],scaling=constrained);" }}} {EXCHG {PARA 0 "" 0 "" {TEXT 256 50 "The following example is from pag e 470, example 4." }}{PARA 0 "" 0 "" {TEXT -1 9 "Example 2" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 33 "x:=2*(t-sin(t)); y:=2*(1-cos(t));" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 22 "plot([x,y,t=0..2*Pi]);" } }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 14 "d1:=diff(x,t);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 14 "d2:=diff(y,t);" }}}{EXCHG {PARA 0 " > " 0 "" {MPLTEXT 1 0 40 "L:=Int(((d1)^2+(d2)^2)^(1/2),t=0..2*Pi);" }} }{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 9 "evalf(%);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 42 "plot([x,y,t=0..4*Pi],scaling=constrained) ;" }}}{EXCHG {PARA 0 "" 0 "" {TEXT 257 11 "Exercise 1." }}{PARA 0 "" 0 "" {TEXT -1 81 "Estimate the length of the arc of the hyperbola xy = 1 from (1, 1) to (2, 1/2). " }}{PARA 0 "" 0 "" {TEXT 258 12 "Exercis e 2. " }}{PARA 0 "" 0 "" {TEXT -1 108 "If x=exp(t)*cos(t) and y=exp( t)*sin(t), where t is in [0,2*Pi], plot the graph and find its arc \+ length." }}{PARA 0 "" 0 "" {TEXT 259 11 "Exercise 3." }}{PARA 0 "" 0 " " {TEXT -1 280 "The the function f below represents a telephone wire hanging between two poles x = -5 and x = 5. It takes the shape of a c atenary. Note that the value 'a' represents the lowest height of the w ire above the ground. Find the arc lengths for the wire with a=5 and a =6 respectively." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "restart;" }}}{EXCHG {PARA 0 " > " 0 "" {MPLTEXT 1 0 44 "f:=proc(a,x) (a/2)*(exp(x/a)+exp(-x/a)) end; " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 7 "f(5,x);" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 43 "Some more interesting parametric equation s." }}{PARA 0 "" 0 "" {TEXT -1 11 "Example 3. " }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 21 "x := cos(7*t)*sin(t);" }{TEXT -1 0 "" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 21 "y:= cos(-3*t)*cos(t);" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 20 "plot([x,y,t=0..Pi]);" }}} {EXCHG {PARA 0 "" 0 "" {TEXT -1 10 "Example 4." }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 26 "x := cos(t)*sin(2*t); " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 20 "y:= cos(4*t)*sin(t);" }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 22 "plot([x,y,t=-Pi..Pi]);" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 10 "Example 5." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 18 "x := t*sin(t); " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 18 "y:= t^2 - t^(1/3);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 23 "plot ([x,y,t=0..16*Pi]);" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 10 "Example 6. " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "x := 2*t; " }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 30 "y:= exp(-t)*cos(t) + t*cos(t );" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 23 "plot([x,y,t=0..16*Pi] );" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 10 "Example 7." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 79 "x := sin(t)*cos(t) + sin(2*t)*cos(2 *t) + sin(3*t)*cos(3*t) + sin(4*t)*cos(4*t);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 81 "y := sin(t)*cos(2*t) + sin(3*t)*cos(4*t) + sin(5 *t)*cos(6*t) + sin(7*t)*cos(8*t);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 23 "plot([x,y,t=0..16*Pi]);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 45 "plot([37*sin(15*t), 89*cos(20*t), t=0..100]);" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "> " 0 " " {MPLTEXT 1 0 0 "" }}}}{MARK "28 0 0" 0 }{VIEWOPTS 1 1 0 3 2 1804 1 1 1 1 }{PAGENUMBERS 0 1 2 33 1 1 }