Sequence that a sequence

is defined recursively by the equations

and

It is not hard to prove by mathematical induction that this sequence is
increasing and bounded above and that, consequently, it converges.
Furthermore, if

then, letting

in the equation

we obtain

Since this equation can be expressed in quadratic form we can solve it easily
obtaining

We know that if

for all

then the number

must be a fixed point of this function

To find this fixed point graphically we draw the graph of

and the line

in the same system. Where these two graphs intersect is the required fixed
point.

We look at the equation

and calculate a sequence of iterates of the function

starting at the number

[This is sort of like the 'coweb' method below]. You will obtain

This table suggests very strongly that the limit of the given sequence is
about

In this example we look at the sequence

defined by

and

for each

It is easy to see that this sequence is increasing and that it is unbounded
above. Consistent with this observation is the fact that the equation

has no real solution. If we look for a fixed point of the function

defined by

by plotting the graph of

in the same system as the line

then we obtain the next figure that shows that the two graphs do not
intersect.

Finally, if we define

and make a column of iterates then we see compelling evidence that

as



A cobweb diagram is a graphical method of looking at the sequence

generated by a dynamical system

This
can be demonstrated by the following diagram:

Newton's method is based on the observation that the tangent line is a good
local approximation to to the graph of a function. If

is a point on the graph of the function

The tangent line at this point is

The

intercept
of this line (by setting

yield,

Base
on this idea, here is the Newton's method:

For each of the following recursively defined sequences, show that the sequence is monotone, try to decide whether or not it is bounded, try to find the limit yourself and then find the limit.
We define

and for each

we have

We define

and for each

we have

We define

and for each

we have

We define

and for each

we have

We define

and for each

we have

Can
you see why the limit of this sequence is
