/** A solution to the TresAmigos problem.
 * @see http://www.radford.edu/itec120/2009spring-ibarland/Homeworks/hw05.html
 * @author Ian Barland
 * @version 2008.Oct.16-b
 *
 * This version creates two helper functions to help make our main task easier:
 * 'minString' and 'maxString'.
 * These make it easy to find the first name (minimum out of three),
 * and the last name (maximum of three).
 * Then, in a totally non-intuitive way, it also determinines the
 * middle name using *only* min and max (!).
 * 
 * While the code is short, it is *not* obviously-correct;
 * therefore it is *not* as good as (say) the previous v2 solution.
 * The only reason I have faith in the code is because the test cases 
 * were extremely thorough, and it passes those test cases.
 */
public class TresAmigos_v3 {
    private String first,second,third;
    
    public TresAmigos_v3( String ami1, String ami2, String ami3 ) {
        this.first  = minString3(ami1,ami2,ami3 );
        this.third  = maxString3(ami1,ami2,ami3 );
        this.second = maxString3( maxString(minString(ami1,ami2), minString(ami1,ami3)),
                                  maxString(minString(ami2,ami1), minString(ami2,ami3)),
                                  maxString(minString(ami3,ami1), minString(ami3,ami2)) );
        }
     
    public String getFirst()  { return this.first; }
    public String getSecond() { return this.second; }
    public String getThird()  { return this.third; }
     
    private String minString( String s1, String s2 )
    {
        if (s1.compareTo(s2) < 0) 
        {
            return s1;
        }
        else
        {
            return s2;
        }
    }

    private String maxString( String s1, String s2 ) 
    {
        if (s1.compareTo(s2) > 0) {
            return s1;
        }
        else
        {
            return s2;
        }
    }
     
     
    private String maxString3( String s1, String s2, String s3 ) {
        return maxString(s1, maxString(s2,s3) );
        }
    
    private String minString3( String s1, String s2, String s3 ) {
        return minString(s1, minString(s2,s3) );
        }

    }